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Bulletin – June 2016
Equation (A1)
π
t
r
=
α
0
+
α
1
π
t
−
1
e
+
∑
i
=
1
5
α
2
,
i
Δ
u
l
c
t
−
i
+
∑
j
=
1
8
α
3
,
j
Δ
m
p
t
−
j
+
μ
t
MathType@MTEF@5@5@+=feaagCart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=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@6C97@