Skip to content
Bulletin – September 2015
Equation (A3)
E
=
A
Φ
[
d
1
]
−
L
e
−
μ
τ
Φ
[
d
]
,
d
1
=
ln
[
A
L
]
+
(
μ
+
σ
A
2
2
)
τ
σ
′
A
τ
,
d
2
=
d
1
−
σ
A
τ
,
σ
A
=
E
σ
E
A
Φ
(
d
1
)
MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9 vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=x fr=xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGceaqabeaacaWGfb Gaeyypa0JaamyqaiabfA6agnaadmaabaGaamizamaaBaaaleaacaaI XaaabeaaaOGaay5waiaaw2faaiabgkHiTiaadYeacaWGLbWaaWbaaS qabeaacqGHsislcqaH8oqBcqaHepaDaaGccqqHMoGrdaWadaqaaiaa dsgaaiaawUfacaGLDbaacaGGSaaabaGaamizamaaBaaaleaacaaIXa aabeaakiabg2da9maalaaabaGaciiBaiaac6gadaWadaqaamaalaaa baGaamyqaaqaaiaadYeaaaaacaGLBbGaayzxaaGaey4kaSYaaeWaae aacqaH8oqBcqGHRaWkdaWcaaqaaiabeo8aZnaaDaaaleaacaWGbbaa baGaaGOmaaaaaOqaaiaaikdaaaaacaGLOaGaayzkaaGaeqiXdqhaba Gafq4WdmNbauaadaWgaaWcbaGaamyqaaqabaGcdaGcaaqaaiabes8a 0bWcbeaaaaGccaGGSaaabaGaamizamaaBaaaleaacaaIYaaabeaaki abg2da9iaadsgadaWgaaWcbaGaaGymaaqabaGccqGHsislcqaHdpWC daWgaaWcbaGaamyqaaqabaGcdaGcaaqaaiabes8a0bWcbeaakiaacY caaeaacqaHdpWCdaWgaaWcbaGaamyqaaqabaGccqGH9aqpdaWcaaqa aiaadweacqaHdpWCdaWgaaWcbaGaamyraaqabaaakeaacaWGbbGaeu OPdy0aaeWaaeaacaWGKbWaaSbaaSqaaiaaigdaaeqaaaGccaGLOaGa ayzkaaaaaaaaaa@7B0F@